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2(l^2-l-3000)=0
We multiply parentheses
2l^2-2l-6000=0
a = 2; b = -2; c = -6000;
Δ = b2-4ac
Δ = -22-4·2·(-6000)
Δ = 48004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48004}=\sqrt{4*12001}=\sqrt{4}*\sqrt{12001}=2\sqrt{12001}$$l_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{12001}}{2*2}=\frac{2-2\sqrt{12001}}{4} $$l_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{12001}}{2*2}=\frac{2+2\sqrt{12001}}{4} $
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